CSIR NET Exam Pattern for june 2021 with highest cutoff qualify for JRF

 Hello friends, myself Laxman Sonale, in today's article, we see the CSIR NET exam pattern for June 2021 with the highest cutoff qualify for the JRF plan. so in this, we see each different part analysis.

so let's start

CSIR NET Exam Pattern for June 2021 with highest cutoff qualify for JRF

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CSIR Net Exam is knocking on the door ( 29 January 2021) so many don't know about the CSIR NET Exam Pattern.

So those students know about exam patterns, they may ask or most students ask these questions, 

How many questions, we should attend to qualify for CSIR NET JRF?

-So the CSIR NET exam pattern is the same as previous ers, nothing is changing.

- so how many questions, you should attend and answer correctly in each different part of the exam.

- So that you can qualify for CSIR NET JRF or LS

- so what is the number of questions, you should have to attend?

- In this blog, I am giving the best plan in brief information about a different part, different sections that are present in the CSIR NET exam.

- And among different parts, how many numbers of the questions, you should attend, and how many of them attend correctly.

- Let's divide three different parts of the CSIR NET Exam. Part A, Part B, and Part C.

- In Part C, the total number of questions is answered by 25 out of 75 questions.

- In part B, the total number of questions is answered by35 out of 50 questions.

- In Part A, a total number of questions is answered by 15 out of 20 questions.

- These are basic criteria for CSIR NET Exam Pattern.

- So the Part C, there are more choices as compared to part B and Part A.

- In Part C, each question have 4 marks

- In Part B, each question have 2 marks

- In part A, each question has 2 marks.

- so this exam has a negative (-ve) marking scheme

- In part C for every wrong answer the Negative(-ve) mark is (-1) means if you give one question wrong for this (4 marks for the question and 1 mark of right answer means you lose for 1 wrong answer is 5 mark.)

- In part B and Part A, for every wrong answer the -ve mark is (0.5) means you lose ( 2 mark for the wrong question and 0.5 mark of the right answer)

- So this is the total marking scheme for CSIR NET Exam.

- So how many questions you must attend,

to answer that this question, see the following explanation.

- In Part C, you should attend 22-24 questions ( so this should be your target for CSIR NET Exam)

- So let's assume that the minimum questions are minimum question is 22 and the maximum question is 24, you can attend.

- In Part B, you should attend 20-22, you should say, this much only,

the reason is that Part B is the memory base section and the question is all on how much you can remember, so you can't give the correct answer with confidence.

But if you preferred well, then hit the 35 questions in part B.

- In Part A, you should attend, 8-10 questions

lets summaries from Part C to part A

- In Part C, 22-24 questions, in Part B, 20-22, and in Part A, 8-10 questions

In part C, I take more questions than part B and Part A

Because in Part C there are more choices means more question is available.

- Now let's calculate

- In every part, we have a minimum number of questions and a maximum number of questions in different parts.

- So for a minimum number of questions, let's calculate and after these calculations, then calculate a maximum number of questions also, if you attend them.

- So if you answer 22 questions in Part C, and assume, all of them are correct, then you get a mark is about 88 ( 22* 4 = 88).

- In Part B, the minimum number of questions is 20, if you attend all and all are correct, then you get 40 ( 20 * 2= 40).

- In part A, the minimum number of questions is 8, if you attend all and all are correct, then you get a 16 mark ( 8 * 2 = 16)

- So lets the sum up all minimum numbers of question obtained marks.

Part C + Part B + Part A = 88 + 40 +16 = 144 marks.

so

As you may know, the previous year's cut-off is about 120 or less or more 5 mark. so 120 marks is enough to get a JRF this is for the general category

- here we take the general category cut-off, because, this category cutoff is high than other categories.

- If you qualify for that's mark, then you qualify for other all-category cut-offs.

- So 144 marks is enough to qualify for JRF.

- remember one thing, this is just considering facts is all questions are correct.

so In reality, this is not happening, because, number of questions you attend is not correct.

- so what will happen if some of them are the wrong answer.

so let's assume in Part C, in 22 questions, in between them the 4 questions go wrong, so for 4 wrong answers, your mark is deducted as follows

- So for each wrong answer is 4 so, 4*4 = 16 + 4(-ve marking) = 20

then from 88 - 20 = 68 is score for part C

- In part B, let's assume 6 questions answer goes wrong, then calculations as follows

6 * 2.5( 2 mark of question + 0.5 mark of -ve marking) = 15 marks

so from 40 - 15 = 25 is score for part B

- In Part A, assume 2 questions  answer is goes wrong, then

2 * 2.5 = 5

from 16 - 5 = 11

so let's see, how much mark will come, when considering some of them is wrong

68 + 25  + 11 = 104 ( 52%)

so this is your borderline score.

- If 104 is (52%) so the time JRF cut-off is equal to this, but most of the time the cut-off is more.

- So 52% is sufficient for LS, if LS cutoff is under this

- So maximum questions attending criteria is awesome to qualify CSIR NET exam JRF.

-You still have room for errors if the wrong answer like

- In Part C, 4 questions answer is wrong and in Part B 6 questions answer is wrong and In part A 2 questions answer is wrong.

- So you can qualify for LS but there is no guarantee to qualify for JRF, so for JRF what can we should do, let's see the following explanation.

- So For JRF you should attend maximum (more) number of questions, as we consider earlier

let's take, 24 * 4 = 96 in part C 

in Part B, let's take, 22 * 2 = 44

In part A, let's take 10 * 2 = 20

- let's sum of maximum number of questions marks = 96 + 44 + 20 = 160

come,if you take, 24 in part C, 22 in part B, and 10 in part A.

- if all questions you attend are all correct.

so 160 mark score is a very good score, you qualify for JRF, no matter what is the cutoff for all categories.

- Again taking wrong answers of questions in different parts, what will happen.

let's assume, same things,

- In part C, your 4 questions answer goes wrong 4 * 5 = 20

so 96 - 20 = 76 is score of Part C

- In Part B, your 6 questions answer goes wrong 6 * 2.5 = 15

so  44 - 15 = 29 is score of Part B

- In Part A, your 2 questions answer goes wrong 2 * 2.5 = 5

so, 20 - 5 = 15

- let's add wrong answers score after deductions of the mark,

76 + 29 + 15 = 120 ( 60%)

- This is a kind of exact mark, we need to qualify for exam for the general category.

but some time cutoff is more than 120.

- So in general 60% mark is good enough for general category.

So if you attend 24 questions in Part C, and between them, 4 goes wrong

In Part B, if you attend 22 questions in part B and between them 6 goes wrong.

In Part A, if you attend 10 questions, and between them, 2 goes wrong

so you can still qualify for JRF, in a general category, with this many questions is solved.

so this is all about the CSIR NET Exam Pattern for June 2021 with the highest cutoff qualify for JRF

Read More:-

1) CSIR NET Exam june 2021 date notification

hey friends, if you read carefully then you should understand this exam pattern, if after reading this, you cant' understand, then

see the following video

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